The path of a projectile moving under gravity is given by y = x – 
, where x and y are in meters, use g = 10m/s 2 . For this projectile to match the following column.
Column I | Column II |
(i) Angle of projection | [A] 20m |
(ii) Angle made by instantaneous velocity with horizontal after 4sec | [B] 80 m |
(iii) Maximum height attained | [C] 45º |
(iv) Maximum horizontal distance moved | [D] tan–1(1/2) |
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Ans.
(i) [C]
(ii) [C]
(iii) [A]
(iv) [B]
Sol. 
as 
and 
for Range put 
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